## What are the divisors of 48?

Divisors of numbers

Number | Prime factorization | Divisors |
---|---|---|

47 | 47 | 1, 47 |

48 | 24 * 3 | 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 |

49 | 72 | 1, 7, 49 |

50 | 52 * 2 | 1, 2, 5, 10, 25, 50 |

## What are divisors of 91?

What is the list of divisors from 1 to 100?

Number | List of Divisors |
---|---|

Divisors of 91 | 1,7,13,91 |

Divisors of 92 | 1,2,4,23,46,92 |

Divisors of 93 | 1,3,31,93 |

Divisors of 94 | 1,2,47,94 |

**How do you know how many divisors a number has?**

In general, if you have the prime factorization of the number n, then to calculate how many divisors it has, you take all the exponents in the factorization, add 1 to each, and then multiply these “exponents + 1″s together.

**What is the factors for 48?**

Prime factorization is an extension of factorization in which all the factors are prime numbers. For example, suppose we want the prime factorization of 48 . The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 .

### What are the multiples of 48?

Solution: The first ten multiples of 48 are, 48, 96, 144, 192, 240, 288, 336, 384, 432 and 480.

### What is the sum of all divisors of 91?

The number 91 can be divided by 4 positive divisors (out of which 0 are even, and 4 are odd). The sum of these divisors (counting 91) is 112, the average is 28.

**How do you find the divisors of a number in Python?**

Finding divisors of a number with Python

- def get_divisors(n): for i in range(1, int(n / 2) + 1): if n % i == 0: yield i yield n.
- def prime_factors(n): i = 2 while i * i <= n: if n % i == 0: n /= i yield i else: i += 1 if n > 1: yield n.

**How do you find the divisors of 12?**

So, the divisors or factors of the number 12 are 1,2,3,4,6 and 12.

#### How do you make 48?

The factor pairs of the number 48 are: 1 x 48, 2 x 24, 3 x 16, 4 x 12, and 6 x 8. When you multiply each of these factor pairs together, you get 48….