## How do you calculate the number of photons emitted per second?

According to the equation E=n⋅h⋅ν (energy = number of photons times Planck’s constant times the frequency), if you divide the energy by Planck’s constant, you should get photons per second.

**How do you calculate the energy of a photon emitted?**

Photons velocity equals the speed of light. Photons are massless, but they have energy E = hf = hc/λ. Here h = 6.626*10-34 Js is called Planck’s constant. The photon energy is inversely proportional to the wavelength of the electromagnetic wave.

**How many photons are in a beam of light?**

Photons are light. One photon equals one unit of light. A light source can send one photon or many trillions or billions of photons.

### What is the relationship between the number of photons and the intensity of light?

In the particle model of light, a higher intensity (brighter light) means more photons. Technically, we should say that a higher intensity corresponds to a greater number of photons passing through a given area in a given amount of time.

**How many photons are emitted per second by a 5mw?**

Thus the number of photons emitted per second =3.

**How many photons per second does the light emit?**

The answer is approximately 10^45 photons every second.

#### How many photons are emitted per second by a 10mw?

Approximately 3.15 * 10^(16) photons per second.

**How many photons does a laser emit per second?**

A laser pointer typically has a power rating of 1 mW, or 0.001 Joules per second. This means that every second a laser pointer emits a number of photons equal to (3.2x1018photons/J)(0.001J/s) = 3.2×1015 photons/s.

**How many photons hit the Earth every second?**

How many reach earth? If we use the 1e45 figure for photons/sec emitted by the Sun, then you get ~1.8e36 photons striking the Earth per sec and 4.4e16 photons per sec hitting the eye (assuming a pupil diameter of 2mm.)

## Is intensity photons per second?

intensity is the number of photons incident in a second on a unit area ( more accurately it is the energy per unit area per unit time), while frequency refers to the frequency of the photon when referred to as a wave which is the number of waves per second.

**Which of the following refers to the number of photons per unit area and time emitted from a light source?**

Intensity is the total amount of energy falling on (or going through) a surface/region per unit area A per unit time t and therefore measured in J/(m2s). For monochromatic radiation, the total energy emitted equals the number of photons n times the energy of one photon, hν.

According to the equation E=n⋅h⋅ν (energy = number of photons times Planck’s constant times the frequency), if you divide the energy by Planck’s constant, you should get photons per second. Eh=n⋅ν → the term n⋅ν should have units of photons/second. Click to see full answer. Furthermore, how do you calculate the number of photons emitted per second?

**How much energy does it take to take out one photon?**

Correct option is C 2.67×1019. P = 10 W(given) this means E in 1 sec = 10 J % used to convert into photon = 90% (given) ∴Energy used = 9 J Energy used to take out 1 photon = hc/λ = 6.63* 10-34* 3 * 108/590 * 10-9= 6.633/590 * 10-17

### What is the wavelength of light emitted by a 100-watt bulb?

A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb. Was this answer helpful?

**What is the potential difference of a photoelectric cell?**

A photoelectric cell is connected to a source of variable potential difference, connected across it and the photoelectric current resulting (μA)is plotted against the applied potential difference (V). The graph in the broken line represents one for a given frequency and intensity of the incident radiation.